1 条题解
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LightOJ官方:
#include <bits/stdc++.h> /** * Returns the total number of problems. * * @param a denotes the number of problems in the first computer * @param b denotes the number of problems in the second computer */ int sum(int a, int b) { return a+b; // Implement this method } /** * Takes care of the problem input and output. */ int main() { int cases; scanf("%d", &cases); for (int caseno = 1; caseno <= cases; ++caseno) { int a, b; scanf("%d %d", &a, &b); printf("Case %d: %d\n", caseno, sum(a, b)); } return 0; }
- 1
信息
- ID
- 605
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 10
- 标签
- 递交数
- 4
- 已通过
- 1
- 上传者